In this article, we will see that the Cutting Length of Stirrups is calculated as follows. We have also become a calculator for this cutting length. Click “Calculator for Cutting Length of Stirrups” on this article for its link.
- Cutting Length for Rectangular Stirrups
- Cutting Length for Square Stirrups
- Cutting Length for Circular Stirrups
- Cutting Length for Helical Stirrups
- Cutting Length for Triangle Stirrups
- Cutting Length for Diamond Stirrups
Most Important Point In This Article
Cutting Length Formula for Reinforcement
- Length of reinforcement inside the beam & Column + Hook Length for Stirrups – Bend inside the Stirrup Shape (Ring)
Length of Reinforcement Inside the Beam & Column.
- Steel (Rainfoecemnt) inside the beam and column which is based on Stirrup Shape. In which we take its periphery as the steel length.
- The calculation of this length is done by subtracting the cover from the first one.
Hook Length for Stirrups ( As per IS 2502:1963 )
k in 2 in the case of Mild Steel conforming, ( As per IS 2502:1963, P-6, Note-1 )
k in 3 in the case of Medium Tensile Steel conforming, ( As per IS 2502:1963, P-6, Note-1 )
k in 4 in the case of Cold-worked Steel conforming, ( As per IS 2502:1963, P-6, Note-1 )
Most IMP (As per IS 2502:1963, P-6, Table-II, Note )
H = Hook allowance is taken as 9d, 11d, 13d, and 17d for k values 2, 3, 4 and 6 respectively and rounded off to the nearest 5 mm, but not less than 75 mm.
B = Bend allowance is taken as 5d, 5.5d, 6d, and 7d for k values 2, 3, 4 and 6 respectively and rounded off to the nearest 5 mm, but not less than 75 mm. 45° Bend = 1d, 90° Bend = 2d, 135° Bend = 3d (d = Dia of Stirrups)
Hook Length As Per Is Code
Sr.No. | Shape | Hook Length As Per Is Code | Single Ling Diagram | Cutting Length Formula for Reinforcement (d = Steel Dia) |
1 | 2 (A + E) + 24d | 2 (A + E) + 24d | ||
2 | 2 (A + E) + 20d | 2 (A + E) + 20d | ||
3 | 2A + E + 28d | 2A + E + 28d | ||
4 | L + 2H | L+2H = L + 2 x (4d+ d+2kd) = L + ( 4d +4d +d) x2 = L + 18d |
||
5 | Where P is not greater than D/5 N = Number of complete and fractional turns D = Internal dia P = Pitch of helix d = Size of barN π (D + d) + 8d |
– | N π (D + d) + 8d | |
B | 4C + 24d | 4C + 24d | ||
C | 4C + 20d | 4C + 20d |
#1. Cutting Length for Rectangular Stirrups
As per the drawing of the above column. We see some data. Which is as follows.
Step 1. Collect Data as Per Drawing
- Clear Cover: 25 mm
- Column Size: 200 mm x 600 mm
- Dia of Stirrups: 8 mm
Step 2. Apply Cutting Length Formula
Cutting Length Formula for Rectangular Beam and Column ( as Per Is 2502:1963 Page – 6 )
Formula of Cutting Length for Beam and Column Stirrup = 2 (a+b) + hooks (24 d) – 3 numbers of 90° bends – 2 numbers of 135° bends
Step 3. Find Data According to Formula
Lenth of stirrups a side = 600 – 2 side of the cover = 600 – (2 x 25 mm) = 550 mm
Lenth of stirrups b side = 200 – 2 side of the cover = 200 – (2 x 25 mm) = 150 mm
Step 4. After Finding the Data, Put That Data in the Formula and Count on It
Cutting Length for Beam and Column Stirrup = 2 (a+b) + hooks (24 d) – 3 numbers of 90° bends – 2 numbers of 135° bends
= 2 x (a + b) + (24 x d ) – (3 x 2d) – (2 x 3d)
= 2 x (550+150) + (24 x 8 (d = 8 mm stirrups) ) -(3 x 2 x 8) – (2 x 3 x 2)
= 1400 + 192 – 48 – 48
Step 5. All the Calculated Answer Is Cutting Length for Rectangular Beam and Column Stirrup.
Cutting Length for Rectangular Beam and Column Stirrup= 1496 mm or 1.496 m3
Also, Read: How to Calculate Slab Steel Quantity from Drawing | BBS of Slab
#2. Cutting Length for Square Stirrups
As per the drawing of the above column. We see some data. Which is as follows.
Step 1. Collect Data as Per Drawing
- Clear Cover: 25 mm
- Column Size: 400 mm x 400 mm
- Dia of Stirrups: 8 mm
Step 2. Apply Cutting Length Formula
Cutting Length Formula for Square Beam and Column ( as Per Is 2502:1963 Page – 6 )
Formula of Cutting Length for Beam and Column Stirrup = 2 (a+b) + hooks (24 d) – 3 numbers of 90° bends – 2 numbers of 135° bends
Step 3. Find Data According to Formula
Lenth of stirrups x side = 400 – 2 side of the cover = 400 – (2 x 25 mm) = 350 mm
Lenth of stirrups y side = 400 – 2 side of the cover = 400 – (2 x 25 mm) = 350 mm
Step 4. After Finding the Data, Put That Data in the Formula and Count on It
Cutting Length for Beam and Column Stirrup = 2 (a+b) + hooks (24 d) – 3 numbers of 90° bends – 2 numbers of 135° bends
= 2 x (a + b) + (24 x d ) – (3 x 2d) – (2 x 3d)
= 2 x (350+350) + (24 x 8 (d = 8 mm stirrups) ) -(3 x 2 x 8) – (2 x 3 x 2)
= 1400 + 192 – 48 – 48
Step 5. All the Calculated Answer Is Cutting Length for Square Beam and Column Stirrup.
Cutting Length for Square Beam and Column Stirrup= 1496 mm or 1.496 m
Also, Read: How to Calculate Staircase | Concrete & Bar Bending Schedule (BBS) | Staircase Reinforcement Details
#3. Cutting Length for Circular Stirrups
As per the drawing of the above column. We see some data. Which is as follows.
Step 1. Collect Data as Per Drawing
- Clear Cover: 50 mm
- Column Diameter: 300 mm
- Dia of Stirrups: 8 mm
Step 2. Apply Cutting Length Formula
Cutting Length Formula for Circular Column ( as Per Is 2502:1963 Page – 6 )
Formula of Cutting Length for Circular Stirrup = Circumference of Ring + 2 numbers of hooks – 2 numbers of 135° bends
Step 3. Find Data According to Formula
Where,
Circumference of ring = 2丌r (where r – Radius),
We know (r) radius of circle = d/2 (half of the diameter)
Diameter of Ring (d) = Diameter of Column (D) – Clear Cover = 300 – 50 – 50 = 200 mm
Radius of Ring r = d/2 = 200/2 = 100 mm
Step 4. After Finding the Data, Put That Data in the Formula and Count on It
So,
Length of Circular ring formula = 2丌r + (2 x 10d) – (2 x 3d)
= (2 x 丌 x 100) + (2 x 10 x 8 ) – (2 x 3 x 8)
= 628 + 160 – 48
Step 5. All the Calculated Answer Is Cutting Length for Circular Stirrups.
Cutting Length for Circular Stirrups = 740 mm or 0.74 m
Also, Read: What Is Staircase | Staircase Design Calculation Example | Concrete Calculation of Staircase
#4. Cutting Length for Helical Stirrups
As per the drawing of the above column. We see some data. Which is as follows.
Step 1. Collect Data as Per Drawing
- Clear Cover: 75 mm
- Column Diameter: 600 mm
- Dia of Stirrups: 8 mm
- Spacing of Stirrups: 200 mm
- Column Length: 20 m
Step 2. Apply Cutting Length Formula
Cutting Length Formula for Helical / Spiral Column ( as Per Is 2502:1963 Page – 6 )
Formula of Cutting Length for Spiral Stirrup = Number of Turns x √ [(Circumference of Stirrup)^{2} +(Spacing of Stirrups)^{2} ]
Step 3. Find Data According to Formula
Number of Turns = Length of Column ÷ Spacing of Stirrups
= 20000 mm ÷ 200
= 100 Numbers Turn.
Circumference of the Stirrups = π × Dia of the Stirrup
Dia of the Stirrups = Dia of Column – ( 2 x Clear Cover )
= 600 – (2 x 75 )
Dia of the Stirrup = 450 mm
So,
Circumference of the Stirrup = π x 450 mm
= 1414.35 mm
Step 4. After Finding the Data, Put That Data in the Formula and Count on It
Let’s putt these values into the formula.
Cutting Length for Spiral Stirrup = Number of Truns x √ [(Circumference of Stirrup)^{2} +(Sapcing of Stirrups)^{2} ]
= 50 x √[ (1414.35 mm )^{2} + ( 200)^{2 }]
= 50 x √[ ( 20,00,385.93 + 40,000) ]
= 50 x √[ ( 20,40,385.93) ]
= 50 x 1428.42 mm
Step 5. All the Calculated Answer Is Cutting Length for Spiral Stirrup.
Cutting Length for Spiral Stirrup = 71,421.00 mm or 71.421 m
Also, Read: What Is Bar Bending Schedule | Preparation as Per Bs 4466 | Tolerances as Per Bs 4466
#5. Cutting Length for Triangle Stirrups
As per the drawing of the above column. We see some data. Which is as follows.
Step 1. Collect Data as Per Drawing
- Clear Cover: 25 mm
- Column Size: 400 mm x 300 mm
- Dia of Stirrups: 8 mm
Step 2. Apply Cutting Length Formula
Cutting Length Formula for Triangle Column ( as Per Is 2502:1963 Page – 6 )
Formula of Cutting Length for Triangle Stirrup = (2 x H) + a + 2 numbers of hooks – 4 numbers of 135° bends
Cutting Length of Triangle Stirrup = (2 x H) + a + (2 x 10d) – (4 x 3d)
Step 3. Find Data According to Formula
Where,
Lenth of stirrups a side = 300 – 2 side of the cover = 300 – (2 x 25 mm) = 250 mm
Lenth of stirrups b side = 400 – 2 side of the cover = 400 – (2 x 25 mm) = 350 mm
Lenth of stirrups H = √[(b^{2 })+(a/2)^{2}] = √(350^{2})+(250/2)^{2}) = 372 mm
Step 4. After Finding the Data, Put That Data in the Formula and Count on It
Cutting Length of Stirrup = (2 x H) + a + (2 x 10d) – (4 x 3d)
= (2 x 372) + (250) + (2 x 10 x 8) – (4 x 3 x 8)
= ( 744) + (250) + (160) – (96)
Step 5. All the Calculated Answer Is Cutting Length of Triangle Stirrup.
Cutting Length of Triangle Stirrup = 1,058 mm or 1.06 m
Also, Read: What Is Well Foundation | Component of Well Foundation
#6. Cutting Length for Diamond Stirrups
As per the drawing of the above column. We see some data. Which is as follows.
Step 1. Collect Data as Per Drawing
- Clear Cover: 25 mm
- Column Size: 400 mm x 300 mm
- Dia of Stirrups: 8 mm
Step 2. Apply Cutting Length Formula
Cutting length formula for Diamond Column ( As per IS 2502:1963 page – 6 )
Formula of Cutting Length for Diamond Stirrup = (4 x H) + hooks (24 d) – 3 numbers of 90° bends – 2 numbers of 135° bends
Step 3. Find Data According to Formula
Lenth of stirrups H = √[(b/2)^{2 }+ (a/2)^{2}]
Lenth of stirrups a side = 300 – 2 side of the cover = 300 – (2 x 25 mm) = 250 mm
Lenth of stirrups b side = 400 – 2 side of the cover = 400 – (2 x 25 mm) = 350 mm
Therefore,
H = √[(b^{2 })+(a/2)^{2}] = √((350/2)^{2}+(250/2)^{2}) = 215 mm
Step 4. After Finding the Data, Put That Data in the Formula and Count on It
Cutting Length of Diamond Stirrup = (4 x H) + (24d) – (3 x 2d) – (2 x 3d)
= (4 × 215) + (24 x 8) – (3 x 2 x 8)-(2 x 3 x 8)
= (860) + (192) – (48) – (48)
Step 5. All the Calculated Answer Is Cutting Length of Diamond Stirrup.
Cutting Length of Diamond Stirrup = 956 mm or 0.96 m
Also, Read: What Are Columns | Different Types of RCC Columns | Round Column Vs Square Column | Pillars Vs Columns
Cutting Length Formula for Reinforcement
- Formula of Cutting Length for Rectangular Beam and Column Stirrup = 2 (a+b) + hooks (24 d) – 3 numbers of 90° bends – 2 numbers of 135° bends
- Formula of Cutting Length for Square Beam and Column Stirrup = 2 (a+b) + hooks (24 d) – 3 numbers of 90° bends – 2 numbers of 135° bends
- Formula of Cutting Length for Circular Stirrup = Circumference of Ring + 2 numbers of hooks – 2 numbers of 135° bends
- Formula of Cutting Length for Spiral Stirrup = Number of Turns x √ [(Circumference of Stirrup)^{2} +(Spacing of Stirrups)^{2} ]
- Formula of Cutting Length for Triangle Stirrup = (2 x H) + a + 2 numbers of hooks – 4 numbers of 135° bends
- Formula of Cutting Length for Diamond Stirrup = (4 x H) + hooks (24 d) – 3 numbers of 90° bends – 2 numbers of 135° bends
Hook Length for Stirrups
- For example, we have a rectangular column. But, the hook length shouldn’t be less than 75mm.
- So, the hook length of our example stirrup is 75mm.
- But if you cut this length of a bar for making the stirrup, it’ll be bigger than the required size.
Stirrups In Columns
- A stirrup refers to a closed loop of the reinforcement bar. Its main purpose is to hold the reinforcement bars together in an RCC structure.
- When used in a column, they provide lateral support to the main reinforcement bars to prevent buckling.
- They also prevent columns and beams from buckling.
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