In this article, we will see that the** Cutting Length of Stirrups** is calculated as follows. We have also become a calculator for this cutting length. Click “**Calculator for Cutting Length of Stirrups**” on this article for its link.

**Cutting Length for Rectangular Stirrups****Cutting Length for Square Stirrups****Cutting Length for Circular Stirrups****Cutting Length for Helical Stirrups****Cutting Length for Triangle Stirrups****Cutting Length for Diamond Stirrups**

Most Important Point In This Article

## Cutting Length Formula for Reinforcement

**Length of reinforcement inside the beam & Column + Hook Length for Stirrups – Bend inside the Stirrup Shape (Ring)**

### Length of Reinforcement Inside the Beam & Column.

- Steel (Rainfoecemnt) inside the beam and column which is based on
**Stirrup Shape**. In which we take its periphery as the steel length. - The calculation of this length is done by
**subtracting the cover from the first one**.

** Hook Length for Stirrups **( As per IS 2502:1963 )

**Hera**

**k** in **2** in the case of **Mild Steel** conforming, **( As per IS 2502:1963, P-6, Note-1 )**

**k** in **3** in the case of **Medium Tensile Steel** conforming, **( As per IS 2502:1963, P-6, Note-1 )**

**k** in **4** in the case of **Cold-worked Steel** conforming, **( As per IS 2502:1963, P-6, Note-1 )**

Most IMP **(As per IS 2502:1963, P-6, Table-II, Note )**

**H =** Hook allowance is taken as **9d, 11d, 13d, and 17d** for k values **2, 3, 4 and 6** respectively and rounded off to the nearest** 5 mm, but not less than 75 mm.**

**B =** Bend allowance is taken as **5d, 5.5d, 6d,** **and** **7d** for k values **2, 3, 4 and 6** respectively and rounded off to the **nearest 5 mm, but not less than 75 mm. **45° Bend = 1d, 90° Bend = 2d, 135° Bend = 3d (d = Dia of Stirrups)

### Hook Length As Per Is Code

Sr.No. | Shape | Hook Length As Per Is Code | Single Ling Diagram | Cutting Length Formula for Reinforcement (d = Steel Dia) |

1 | 2 (A + E) + 24d | 2 (A + E) + 24d | ||

2 | 2 (A + E) + 20d | 2 (A + E) + 20d | ||

3 | 2A + E + 28d | 2A + E + 28d | ||

4 | L + 2H | L+2H = L + 2 x (4d+ d+2kd) = L + ( 4d +4d +d) x2 = L + 18d | ||

5 | Where P is not greater than D/5 N = Number of complete and fractional turns D = Internal dia P = Pitch of helix d = Size of bar N π (D + d) + 8d | – | N π (D + d) + 8d | |

B | 4C + 24d | 4C + 24d | ||

C | 4C + 20d | 4C + 20d |

## #1. Cutting Length for Rectangular Stirrups

As per the drawing of the above column. We see some data. Which is as follows.

### Step 1. Collect Data as Per Drawing

**Clear Cover:**25 mm**Column Size:**200 mm x 600 mm**Dia of Stirrups:**8 mm

### Step 2. Apply Cutting Length Formula

#### Cutting Length Formula for Rectangular Beam and Column ( as Per Is 2502:1963 Page – 6 )

**Formula of Cutting Length for Beam and Column Stirrup** = 2 (**a+b**) + **hooks **(**24 d**) – **3** numbers of **90° bends** – **2** numbers of** 135° bends**

### Step 3. Find Data According to Formula

Lenth of stirrups **a** side = **600** – **2 side of the cover = 600** – (**2 x 25 mm**) = 550 mm

Lenth of stirrups **b** side = **200** – **2 side of the cover = 200** – (**2 x 25 mm**) = 150 mm

### Step 4. After Finding the Data, Put That Data in the Formula and Count on It

Cutting Length for Beam and Column Stirrup = 2 (**a+b**) + **hooks **(**24 d**) – **3** numbers of **90° bends** – **2** numbers of** 135° bends**

= 2 x (a + b) + (24 x d ) – (3 x 2d) – (2 x 3d)

= 2 x (550+150) + (24 x 8 **(d = 8 mm stirrups) **) -(3 x 2 x 8) – (2 x 3 x 2)

= 1400 + 192 – 48 – 48

### Step 5. All the Calculated Answer Is Cutting Length for Rectangular Beam and Column Stirrup.

Cutting Length for Rectangular Beam and Column Stirrup= **1496 mm or 1.496 m3**

Also, Read: How to Calculate Slab Steel Quantity from Drawing | BBS of Slab

## #2. Cutting Length for Square Stirrups

As per the drawing of the above column. We see some data. Which is as follows.

### Step 1. Collect Data as Per Drawing

**Clear Cover:**25 mm**Column Size:**400 mm x 400 mm**Dia of Stirrups:**8 mm

### Step 2. Apply Cutting Length Formula

#### Cutting Length Formula for Square Beam and Column ( as Per Is 2502:1963 Page – 6 )

**Formula of Cutting Length for Beam and Column Stirrup** = 2 (**a+b**) + **hooks **(**24 d**) – **3** numbers of **90° bends** – **2** numbers of** 135° bends**

### Step 3. Find Data According to Formula

Lenth of stirrups **x** side = **400** – **2 side of the cover = 400** – (**2 x 25 mm**) = 350 mm

Lenth of stirrups **y** side = **400** – **2 side of the cover = 400** – (**2 x 25 mm**) = 350 mm

### Step 4. After Finding the Data, Put That Data in the Formula and Count on It

Cutting Length for Beam and Column Stirrup = 2 (**a+b**) + **hooks **(**24 d**) – **3** numbers of **90° bends** – **2** numbers of** 135° bends**

= 2 x (a + b) + (24 x d ) – (3 x 2d) – (2 x 3d)

= 2 x (350+350) + (24 x 8 **(d = 8 mm stirrups) **) -(3 x 2 x 8) – (2 x 3 x 2)

= 1400 + 192 – 48 – 48

### Step 5. All the Calculated Answer Is Cutting Length for Square Beam and Column Stirrup.

Cutting Length for Square Beam and Column Stirrup= **1496 mm or 1.496 m**

Also, Read: How to Calculate Staircase | Concrete & Bar Bending Schedule (BBS) | Staircase Reinforcement Details

## #3. Cutting Length for Circular Stirrups

As per the drawing of the above column. We see some data. Which is as follows.

### Step 1. Collect Data as Per Drawing

**Clear Cover:**50 mm**Column Diameter:**300 mm**Dia of Stirrups:**8 mm

### Step 2. Apply Cutting Length Formula

#### Cutting Length Formula for Circular Column ( as Per Is 2502:1963 Page – 6 )

**Formula of Cutting Length for Circular Stirrup** = Circumference of Ring + 2 numbers of **hooks** – 2 numbers of** 135°** bends

### Step 3. Find Data According to Formula

Where,

**Circumference of ring** = 2丌r (where r – Radius),

We know (r) radius of circle = d/2 (half of the diameter)

Diameter of Ring (d) = Diameter of Column (D) – Clear Cover = 300 – 50 – 50 = 200 mm

Radius of Ring r = d/2 = 200/2 = 100 mm

### Step 4. After Finding the Data, Put That Data in the Formula and Count on It

So,

Length of Circular ring formula = **2丌r + (2 x 10d) – (2 x 3d)**

= (2 x 丌 x 100) + (2 x 10 x 8 ) – (2 x 3 x 8)

= 628 + 160 – 48

### Step 5. All the Calculated Answer Is Cutting Length for Circular Stirrups.

Cutting Length for Circular Stirrups = **740 mm or 0.74 m**

Also, Read: What Is Staircase | Staircase Design Calculation Example | Concrete Calculation of Staircase

**#4. Cutting Length for Helical Stirrups**

As per the drawing of the above column. We see some data. Which is as follows.

### Step 1. Collect Data as Per Drawing

**Clear Cover:**75 mm**Column Diameter:**600 mm**Dia of Stirrups:**8 mm**Spacing of Stirrups:**200 mm**Column Length:**20 m

### Step 2. Apply Cutting Length Formula

#### Cutting Length Formula for Helical / Spiral Column ( as Per Is 2502:1963 Page – 6 )

**Formula of Cutting Length for Spiral Stirrup** = **Number of Turns** x √ [(**Circumference of Stirrup**)** ^{2}** +(

**Spacing of Stirrups**)

**]**

^{2}### Step 3. Find Data According to Formula

**Number of Turns = **Length of Column ÷ Spacing of Stirrups

= 20000 mm ÷ 200

= 100 Numbers Turn.

**Circumference of the Stirrups = π × Dia of the Stirrup**

Dia of the Stirrups = Dia of Column – ( 2 x Clear Cover )

= 600 – (2 x 75 )

Dia of the Stirrup = 450 mm

So,

Circumference of the Stirrup = π x 450 mm

= **1414.35 ****mm **

### Step 4. After Finding the Data, Put That Data in the Formula and Count on It

Let’s putt these values into the formula.

**Cutting Length for Spiral Stirrup = Number of Truns x √ [(Circumference of Stirrup) ^{2} +(Sapcing of Stirrups)^{2} ] **

= 50 x **√[ **(1414.35 mm )** ^{2} + **( 200)

^{2 }]= 50 x **√[ **( 20,00,385.93 + 40,000) **]**

= 50 x **√[ **( 20,40,385.93) **]**

= 50 x 1428.42 mm

### Step 5. All the Calculated Answer Is **Cutting Length for Spiral Stirrup**.

**Cutting Length for Spiral Stirrup** = **71,421.00 mm or 71.421 m**

Also, Read: What Is Bar Bending Schedule | Preparation as Per Bs 4466 | Tolerances as Per Bs 4466

**#5. Cutting Length for Triangle Stirrups **

As per the drawing of the above column. We see some data. Which is as follows.

### Step 1. Collect Data as Per Drawing

**Clear Cover:**25 mm**Column Size:**400 mm x 300 mm**Dia of Stirrups:**8 mm

### Step 2. Apply Cutting Length Formula

#### Cutting Length Formula for Triangle Column ( as Per Is 2502:1963 Page – 6 )

**Formula of Cutting Length for Triangle Stirrup** = (2 x** H**) + **a** + **2** numbers of **hooks** – **4** numbers of **135° bends**

Cutting Length of **Triangle Stirrup** = (2 x H) + a + (2 x 10d) – (4 x 3d)

### Step 3. Find Data According to Formula

Where,

Lenth of stirrups **a** side = **300** – **2 side of the cover = 300** – (**2 x 25 mm**) = **250 mm**

Lenth of stirrups **b** side = **400** – **2 side of the cover = 400** – (**2 x 25 mm**) = **350 mm**

Lenth of stirrups **H **= **√[**(b** ^{2 }**)+(a/2)

^{2}**]**=

**√**(350

**)+(250/2)**

^{2}**) =**

^{2}**372 mm**

### Step 4. After Finding the Data, Put That Data in the Formula and Count on It

Cutting Length of Stirrup = (2 x H) + a + (2 x 10d) – (4 x 3d)

= (2 x 372) + (250) + (2 x 10 x 8) – (4 x 3 x 8)

= ( 744) + (250) + (160) – (96)

### Step 5. All the Calculated Answer Is **Cutting Length of Triangle Stirrup**.

**Cutting Length of Triangle Stirrup** = **1,058 mm or 1.06 m**

Also, Read: What Is Well Foundation | Component of Well Foundation

**#6. Cutting Length for **Diamond **Stirrups **

As per the drawing of the above column. We see some data. Which is as follows.

### Step 1. Collect Data as Per Drawing

**Clear Cover:**25 mm**Column Size:**400 mm x 300 mm**Dia of Stirrups:**8 mm

### Step 2. Apply Cutting Length Formula

#### Cutting length formula for Diamond Column ( As per IS 2502:1963 page – 6 )

**Formula of Cutting Length for Diamond Stirrup =** (4 x** H**) + **hooks **(**24 d**) – **3** numbers of **90° bends** – **2** numbers of** 135° bends**

### Step 3. Find Data According to Formula

Lenth of stirrups **H **= **√[**(b/2)** ^{2 }**+ (a/2)

^{2}**]**

Lenth of stirrups **a** side = **300** – **2 side of the cover = 300** – (**2 x 25 mm**) = **250 mm**

Lenth of stirrups **b** side = **400** – **2 side of the cover = 400** – (**2 x 25 mm**) = **350 mm**

Therefore,

**H **= **√[**(b** ^{2 }**)+(a/2)

^{2}**]**=

**√**((350/2)

**+(250/2)**

^{2}**) =**

^{2}**215 mm**

### Step 4. After Finding the Data, Put That Data in the Formula and Count on It

**Cutting Length of Diamond Stirrup** = (4 x H) + (24d) – (3 x 2d) – (2 x 3d)

= (4 × 215) + (24 x 8) – (3 x 2 x 8)-(2 x 3 x 8)

= (860) + (192) – (48) – (48)

### Step 5. All the Calculated Answer Is **Cutting Length of Diamond Stirrup**.

**Cutting Length of Diamond Stirrup** = **956 mm or 0.96 m**

Also, Read: What Are Columns | Different Types of RCC Columns | Round Column Vs Square Column | Pillars Vs Columns

## Cutting Length Formula for Reinforcement

**Formula of Cutting Length for Rectangular Beam and Column Stirrup**= 2 (**a+b**) +**hooks**(**24 d**) –**3**numbers of**90° bends**–**2**numbers of**135° bends****Formula of Cutting Length for Square****Beam and Column Stirrup**= 2 (**a+b**) +**hooks**(**24 d**) –**3**numbers of**90° bends**–**2**numbers of**135° bends****Formula of Cutting Length for Circular Stirrup**= Circumference of Ring + 2 numbers of**hooks**– 2 numbers of**135°**bends**Formula of Cutting Length for Spiral Stirrup**=**Number of Turns**x √ [(**Circumference of Stirrup**)+(^{2}**Spacing of Stirrups**)]^{2}**Formula of Cutting Length for Triangle Stirrup**= (2 x**H**) +**a**+**2**numbers of**hooks**–**4**numbers of**135° bends****Formula of Cutting Length for Diamond Stirrup =**(4 x**H**) +**hooks**(**24 d**) –**3**numbers of**90° bends**–**2**numbers of**135° bends**

## Hook Length for Stirrups

- For example, we have a rectangular column. But, the
**hook length**shouldn’t be less than 75mm. - So, the
**hook length**of our example**stirrup**is 75mm. - But if you cut this
**length**of a bar for making the**stirrup**, it’ll be bigger than the required size.

## Stirrups In Columns

- A
**stirrup**refers to a closed loop of the reinforcement bar. Its main purpose is to hold the reinforcement bars together in an RCC structure. - When used in a
**column**, they provide lateral support to the main reinforcement bars to prevent buckling. - They also prevent
**columns**and beams from buckling.

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