As per our last article How to Structural Design a Building/House Step by Step Part-1, 2 & 3. In this article, we design slab load, slab depth, slab steel design, Slab beam design. Now in this article, we calculated a column design.

Important Point

## Column Design

Below Steps Column Design.

**1. Column Size.**

**2. Column Min Steel Design.**

**3. Column Ring Size.**

### Column Size

**Pu = (0.4 x fck x Ac) + (0.67 x fy x Asc)**

**Pu** = Axial Load Kn

**Ag** = Gross Area of Column

**fck** = Strength Concrete

**Ac** = **Ag – Asc**

**Asc = **Area Steel Concrete

**Minum Size of column 230 mm **

**Column Min Steel Design**

**Assume 2% Steel Provided.**

**Asc = 0.02 Ag**

**Asc = 0.02 Gross Area of Column |** Sp-16 ,P-229

**Column Ring Size**

**Dia of Internal Ties |** IS 456-2000, P-49

**1.** (1/4) x dia of a larger bar

**2. **6 mm

Provide a larger to two values.

**Pitch of Internal Ties |** IS 456-2000, P-49

**1. **Least Internal Dimension

**2. **16 x Dia. of Smaller Bar

**3.** 300 mm

Provide a smaller of three values.

### Column Size Example

**Load Calculation **

**1.** SlabWeight of Slab =** (62.94 /2) + (180.97/2) = 121.95 kn.**

**2. **Beam End Point weight Along lx = **13.54 kn**

**Weight of Beam** Along Lx = (0.230 x 0.460 x 25) x 3.2 **= 8.464 kn.m **

Along Lx Vu = (8.464 x 3.2) /2 = **13.54 kn**

**3. **Beam End Point weight Along ly = **111.94**** kn**

**Weight of Beam** Along Ly = (0.230 x 0.460 x 25) x 9.2 **= 24.334 kn.m **

Along Ly Vu = (24.334 x 9.2) /2 = **111.94 kn**

**4.** Total load Calculation **= 247.435 kn**

**Column Size**

**Pu = (0.4 x fck x Ac) + (0.67 x fy x Asc)**

**Pu = 247.435 kn**

**fck = 20 N/mm ^{2}**

**fy = 415 N/mm ^{2}**

**Ac = 0.98 Ag**

**Pu = (0.4 x 20 x 0.98 Ag) + (0.67 x 415 x 0.02Ag )**

**247.435 x 10 ^{3} = 13.401 Ag**

Ag = **√** 18496 **mm ^{2} = 136 mm ≅ 230 mm Min mum **

**Column Min Steel Design**

Asc = 0.02 Ag

Asc = 0.02 x 230^{2}

**Asc = 1058 mm ^{2}**

**Provide 4 Nos. 20 mm dia | **SP 16, P. 229

**Column Ring Size**

**Dia of Internal Ties| **IS 456-2000, P 49

**1.** (1/4) x dia of a larger bar

= (1/4) x 20 **= 5mm**

**2. **6 mm

Provided larger **6 mm Ø** lateral ties

But we, Provided **8 mm Ø** lateral ties

**Pitch of Internal Ties |** IS 456-2000, P-49

**1. **Least Internal Dimension =

Least Internal Dimension = 230mm

**2. **16 x Dia. of Smaller Bar

16 x 20 = 320 mm

**3.** 300 mm

Provide a smaller of three values.

Provide pitch = 230 mm c/c

**Provided, 8 mm Ø lateral ties at 230 mm c/c**

**Column**

## How to Structural Design a Building/House Step by Step

## How to Structural Design a Building/House Step by Step – 4 Download Excel Sheet

Also, read: How to Structural Design a Building/House Step by Step Part-1 (One Way Simply Support Slab)

Also, read: How to Structural Design a Building/House Step by Step Part-2 (Two Way Simply Support Slab)

Also, read: How to Structural Design a Building/House Step by Step Part-3 (Slab Beam Design)

Avirat Dhodare says

Where is lintel beam design, plinth beam design, and footing design?