As per our last article How to Structural Design a Building/House Step by Step Part-1, 2 & 3. In this article, we design slab load, slab depth, slab steel design, Slab beam design. Now in this article, we calculated a column design.

## Column Design

Important Point

Below Steps Column Design.

**1. Column Size.**

**2. Column Min Steel Design.**

**3. Column Ring Size.**

### Column Size

**Pu = (0.4 x fck x Ac) + (0.67 x fy x Asc)**

**Pu** = Axial Load Kn

**Ag** = Gross Area of Column

**fck** = Strength Concrete

**Ac** = **Ag – Asc**

**Asc = **Area Steel Concrete

**Minum Size of column 230 mm **

**Column Min Steel Design**

**Assume 2% Steel Provided.**

**Asc = 0.02 Ag**

**Asc = 0.02 Gross Area of Column |** Sp-16 ,P-229

**Column Ring Size**

**Dia of Internal Ties |** IS 456-2000, P-49

**1.** (1/4) x dia of a larger bar

**2. **6 mm

Provide a larger to two values.

**Pitch of Internal Ties |** IS 456-2000, P-49

**1. **Least Internal Dimension

**2. **16 x Dia. of Smaller Bar

**3.** 300 mm

Provide a smaller of three values.

### Column Size Example

**Load Calculation **

**1.** SlabWeight of Slab =** (62.94 /2) + (180.97/2) = 121.95 kn.**

**2. **Beam End Point weight Along lx = **13.54 kn**

**Weight of Beam** Along Lx = (0.230 x 0.460 x 25) x 3.2 **= 8.464 kn.m **

Along Lx Vu = (8.464 x 3.2) /2 = **13.54 kn**

**3. **Beam End Point weight Along ly = **111.94**** kn**

**Weight of Beam** Along Ly = (0.230 x 0.460 x 25) x 9.2 **= 24.334 kn.m **

Along Ly Vu = (24.334 x 9.2) /2 = **111.94 kn**

**4.** Total load Calculation **= 247.435 kn**

**Column Size**

**Pu = (0.4 x fck x Ac) + (0.67 x fy x Asc)**

**Pu = 247.435 kn**

**fck = 20 N/mm ^{2}**

**fy = 415 N/mm ^{2}**

**Ac = 0.98 Ag**

**Pu = (0.4 x 20 x 0.98 Ag) + (0.67 x 415 x 0.02Ag )**

**247.435 x 10 ^{3} = 13.401 Ag**

Ag = **√** 18496 **mm ^{2} = 136 mm ≅ 230 mm Min mum **

**Column Min Steel Design**

Asc = 0.02 Ag

Asc = 0.02 x 230^{2}

**Asc = 1058 mm ^{2}**

**Provide 4 Nos. 20 mm dia | **SP 16, P. 229

**Column Ring Size**

**Dia of Internal Ties| **IS 456-2000, P 49

**1.** (1/4) x dia of a larger bar

= (1/4) x 20 **= 5mm**

**2. **6 mm

Provided larger **6 mm Ø** lateral ties

But we, Provided **8 mm Ø** lateral ties

**Pitch of Internal Ties |** IS 456-2000, P-49

**1. **Least Internal Dimension =

Least Internal Dimension = 230mm

**2. **16 x Dia. of Smaller Bar

16 x 20 = 320 mm

**3.** 300 mm

Provide a smaller of three values.

Provide pitch = 230 mm c/c

**Provided, 8 mm Ø lateral ties at 230 mm c/c**

**Column**

## How to Structural Design a Building/House Step by Step

## How to Structural Design a Building/House Step by Step – 4 Download Excel Sheet

Also, read: How to Structural Design a Building/House Step by Step Part-1 (One Way Simply Support Slab)

Also, read: How to Structural Design a Building/House Step by Step Part-2 (Two Way Simply Support Slab)

Also, read: How to Structural Design a Building/House Step by Step Part-3 (Slab Beam Design)

Avirat Dhodare says

Where is lintel beam design, plinth beam design, and footing design?

Engr. Md. Matiar Rahman Mondol says

It would be better if we get lintel beam design, plinth beam design and footing design.

Thanking you.